In an ap the sum of first 10 terms is - 150
WebIn an Ap of 50 terms the sum of first 10 terms is 210 and sum of its 15 terms is 2565.find the ap Report ; Posted by Amena Haseen 5 years, 5 months ago. CBSE > Class 10 > Mathematics 1 answers; Mohit Sharma 5 years, 2 months ago. Let a be the first term and d be the common difference of the given AP. ... WebNov 16, 2015 · CBSE Class 10 Answered In an AP the first term is 2, the last term is 29 and sum of the terms is 155.Find the common difference of the AP. Asked by chittukala7 16 Nov, 2015, 06:26: PM Expert Answer Answered by 16 Nov, 2015, 06:34: PM Application Videos This video covers an application on distance and height
In an ap the sum of first 10 terms is - 150
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WebApr 11, 2024 · Given the sum of the first 10 terms of an AP is -150 and the sum of the next ten terms which means Sum of first 20 terms - Sum of first 10 terms is -530. Let the first term, common difference of the AP be a and d respectively. Now, ⇒ S₁₀ = 10/2 [ 2a + (10 - 1)d ] ⇒ -150 = 5 [ 2a + 9d ] ⇒ 2a + 9d = -30 ...(i) Now, according to the second case, WebThe sum of the first five terms of an AP and the sum of the first seven terms of the same AP is 167. If the sum of the first ten terms of this AP is 235, find the sum of its first twenty …
WebOct 10, 2024 · The sum of the first five terms of an AP and the sum of the first seven terms of the same AP is 167. If the sum of the first ten terms of this AP is 235 , find the sum of its first twenty terms. If sum of first 6 terms of an AP is 36 and that of the first 16 terms is 256 , find the sum of first 10 terms. WebThe sum of n terms of an AP can be easily found out using a simple formula which says that, if we have an AP whose first term is a and the common difference is d, then the formula of the sum of n terms of the AP is S n = …
WebSep 2, 2024 · Best answer i. Sum of first five terms = 150 Sum of the five consecutive terms of arithmetic sequence is five times of its middle term. Third term = 150 5 = 30 150 5 = 30 ii. First term + Tenth term = Second term + Nineth term = Third term + Eighth term = Fourth term + Seventh term = Fifth term + Sixth term = 550 5 = 110 550 5 = 110 WebGiven that sum of the first 10 terms of an A.P. is -150. S 10 = -150 And the sum of next 10 terms is -550. So, the sum of first 20 terms = Sum of first 10 terms + sum of next 10 …
WebJul 29, 2024 · In an AP, the sum of first ten terms is -150 and the sum of its next ten terms is -550. Find the A.P.I have provided the easiest solution of above question, ...
WebIn an AP, the sum of first ten terms is -150 and the sum of next ten terms is -550. Find the AP. dungeons arcane rebornWebSum In an A.P., the sum of first ten terms is −150 and the sum of its next ten terms is −550. Find the A.P. Advertisement Remove all ads Solution Here, we are given S 10 = -150 and sum of the next ten terms is −550. Let us take the first term of the A.P. as a and the common difference as d. So, let us first find a10. dungeons card gameWebFeb 17, 2024 · Sum of first 10 terms = -150. hence we have (10/2) [ 2a + 9d ] = -150 or 2a + 9d = -30 ..................... (1) next 10 terms gives total = -550 . Hence sum of 20 terms = -150 … dungeons a solo adventure gameWebApr 15, 2024 · Best answer Let d be the common difference. Given: first term = a = -4 last term = l = 29 Sum of all the terms = Sn = 150 Sn = n/2 [a + l] 150 = n/2 [-4 + 29] n = 12 There are 12 terms in total. Therefore, 29 is the 12th term of the AP. Now, 29 = -4 + (12 – 1)d 29 = -4 + 11d d = 3 The common difference is 3. ← Prev Question Next Question → dungeons and fightersWebThe sum of first 10 terms of an AP is -150 and the sum of its next 10 terms is -550. Find the AP. Solution Let a be the first term and d be the common difference of the AP. Then, It is … dungeons botwWebThe formula to find the sum of n terms in AP is S n = n/2 (2a+(n−1)d), in which a = first term, n = number of terms, and d = common difference between consecutive terms. What is the Sum of First n Terms of an AP: a, … dungeons cheat tableWebYou would do the exact same process, but you would have to SOLVE for "n" (number of terms) first. To do so, you must start with the arithmetic sequence formula: tn = a + d(n −1) Then, sub in all known values. tn = 15 (last term of the sequence), a = 1 (first term), d = 2 (difference between terms) and solve for n like so: 15 = 1 + 2(n −1) dungeon scented candles